The graph shows the current in a photoelectric effect experiment as a function o

Question

The graph shows the current in a photoelectric effect experiment as a function of the anode- cathode potential difference AV. The light shining on the cathode has a wavelength of 178 nm. 1. Calculate the work function of the cathode metal. 2. What is the power of the incoming ray of 178 nm light hitting the cathode? -3 2 01 2 3 volts 3. If you wanted to increase the number of stop 2.7 V photoelectrons emitted in the experiment, what experimental parameter should you change, and how? Briefly explain your answer.

Explanation / Answer

given that stopping potential is Vstop = -2.7 V

wavelength is lamda = 178 nm

current is I = 1*10^-6 A

1) work function is W = q*Vstop = 1.6*10^-19*2.7 = 4.32*10^-19 J = (4.32*10^-19)/(1.6*10^-19) = 2.7 eV

2) Power P = V*I= 3*1*10^-6 = 3*10^-6 W

3) the no.of photoelectrons emitted are depends on the Intensity of light and frequency of light

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