Solve the problem and answer the following questions. Problem #1: An object with

Question

Solve the problem and answer the following questions. Problem #1: An object with a charge q=-o 09 c is placed in a region of uniform electric field and is released from rest at point A. After the charge has moved to point B, 0.500 m to the right,it has kinetic energy 3 x10 J. (a) If the electric potential at point A is +30Ev, what is the electric potential at point B? (b) what are the magnitude and direction of the electric field? 1) How much did the electric potential energy of this object change during the displacement from A to B? (a) Increased (a) Spontaneous (b)nonspontaneous 2) In moving from A to B the potential energy of the object (b)decreased (c) stay constant 3) The motion from A to B was (c) depends on the direction of the field 4) What is the difference in potential between points A and B? (a) 50 V, with point A at higher potential (b) 50 V, with pint B at higher potential (c) 10 V, with point A at higher potential (d) 10 V, with point B at higher potential 5) What is the voltage at B? 6) What is the magnitude of the electric field? 7) In what direction is the electric field? (a) To the right (b) to the left (c) more information is needed

Explanation / Answer

Change in potential energy = q* change in voltage = kinetic energy

-6*10^(-9)* ( Va-Vb) = 3*10^(-7)

Va-Vb= -50 V

Va= 30*1.6*10^(-19) = (48*10^-19) V

Vb = (48*10^-19- 50) V ( ans)

E = dV/dr = 50/0.5 = 100 N/C from A to B ( ans)

Electric potential energy is decreased by 3*10^-6 J

2) b

3) a

4) a

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