(1 %) Problem 14: A block of mass m-3.5 kg is a constant k 0-240 with respect to
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(1 %) Problem 14: A block of mass m-3.5 kg is a constant k 0-240 with respect to the horizontal, and the coefficient of kinetic friction between the block and the plane is ,-0.12. In the intial position, where the spring is 790 N/m. It is initially at rest on an inclined plane that is at an angle of compressed by a distance of d 0.16 m, the mass is at its lowest position and the spring is compressed the maximum amount. Take the initial gravitational energy of the block as zero. 0 nt Status Randomized Variables m=3.5kg k= 790 Nm d= 0.16 m e 24 ,-0.12 d view Status -V 50% Part (a) what is the block's initial mechanical energy, E0 in r Final Grade 100 Studeer Answer Partial Completed Correct Answer E-10,11 -10.112 Grade Detail Correct Srudent Completed The hat distance, Lin meters will the lock ravel before co ang to test 50% Part () If the spr ng pushes the block up the n line, Completed spring remains attached to both the block and the fixed wall throughout its motion Potestial sin0 cotano asin) acos0 PartialExplanation / Answer
a)
The Initial Mechanical of block is
Eo=(1/2)Kd2=(1/2)*790*0.162
Eo=10.11 J
b)
from work energy theorem
-ukmgL =- mgLSino+(1/2)K(L2-d2)
-0.12*3.5*9.8*L=-3.5*9.8*L*sin24 +(1/2)*790*(L2-0.162)
395L2-9.835L-10.11=0
L=0.173 m
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