(17%) Problem 4: Two parallel conducting plates are separated by 10.2 cm, and on

Question

(17%) Problem 4: Two parallel conducting plates are separated by 10.2 cm, and one of then is taken to be at a potential of zero volts 50% Part (a) what is the electric field strength between them in V/m. if the potential 7.2 cm from the zero volt plate is 455 V? Grade Summarv Deductions Potential 100% sin) 78 9 tan) T acosO atanacotan sinh) coshO tah cotanho cos cotan asi Submissions Attempts remaining: 1:5 (5% per attempt) detailed view 0 Degrees Radians NO DEL CLEAR Submit Hint I give up! Hints: 2% deduction per hint. Hints remaining: 2 Feedback: 2% deduction per feedback. 5006 Part (b) What is the voltage between the plates in V?

Explanation / Answer

Part (a):

here, d = 7.2 cm = 0.072 m

Electric field strength, E = (Change in Potential) / distance = 455 / 0.072 = 6319.4 V/m

Part (b):

Voltage between the plates, V = E*(distance between the plates) = 6319.4*0.102 = 644.6 V

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