questions d, e, f, g, h please (6%) Problem 4: An electron beam is shot into a r

Question

questions d, e, f, g, h please

(6%) Problem 4: An electron beam is shot into a region where there is both an electric field pointing upward of magnitude E 6.1 N/C, and a magnetic field, B, as shown in the figure. While moving through the region the electron beam stays in a straight line with speed v = 160 m/s Randomized Variables E = 611 N/C v = 160 m/s Otheexpertta.com @13% Part (a) In which direction does the electric force act on the electrons? @13% Part (b) In order to keep the electrons in a straight line, in which direction should the magnetic force act? ee 13% Part (c) If the magnetic field can only go between one of the two directions, pointing inside the screen or pointing outside the screen which direction should the magnetic field go? 13% Part (d) Express the magnitude of the electric force using the electric field E and the electron charge e Grade Summary 100% Submissions Attempts remaining: 8 (0% per attempt) detailed view 4 5 6 0 Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. Submission History Hints Feedback Totals Totals 0% 0% 0% | 0% 13% Part (e) Calculate the numerical value of the magnitude of FE, in newtons 13% Part (f) Express the magnitude of the magnetic force in terms of the electron charge e, speed v, and B, the magnitude of the magnetic field 13% Part (g) If the electron is continuing in a straight line, express the magnitude of the magnetic field in terms of v and E 13% Part (h) Calculate the magnitude of the magnetic field if the electron continues in a straight line, in tesla.

Explanation / Answer

d)

magnitude of electric force is given as

Fe = q E

e)

Fe = q E = (1.6 x 10-19) (6.1) = 9.8 x 10-19 N

f)

Fb = magnitude of force by magnetic field = e v B

g)

for the electron to move in straight line

Fe = Fb

e E = e v B

E = v B

h)

B = E/v = 6.1/(160) = 0.038 T

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