Part A A certain reaction has an activation energy of 66.0 kJ/mol and a frequenc

Question

Part A

A certain reaction has an activation energy of 66.0 kJ/mol and a frequency factor of A1 = 1.80×1012 M1s1 . What is the rate constant, k, of this reaction at 26.0 C ?

Express your answer with the appropriate units. Indicate the multiplication of units explicitly either with a multiplication dot (asterisk) or a dash.

Part B

An unknown reaction was observed, and the following data were collected:

Determine the activation energy for this reaction.

Express your answer with the appropriate units.

Explanation / Answer

A)

A = 1.80 x 1012

T = 26 C = 26 + 273 = 299 K

Ea = activation energy = 66000

rate constant is given as

k = A e-Ea/(RT)

k = (1.80 x 1012) e-(66000)/(8.314 x 299)

k = 5.31

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.