.\'ll AT&T; 11:31 AM 53% webassign.net trajectory? (b) At what speed must the pl
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.'ll AT&T; 11:31 AM 53% webassign.net trajectory? (b) At what speed must the player throw the basketball so that the ball goes through the hoop without striking the backboard? 107m/s Need Help?Res A catapult launches a rocket at an angle of 45.8° above the horizontal with an initial speed of 113 m/s. The rocket engine immediately starts a burn, and for 2.64 s the rocket moves along its initial line of motion with an acceleration of 34.3 m/s2. Then its engine fails, and the rocket proceeds to move in free-fall. (a) Find the maximum altitude reached by the rocket. (b) Find its total time of flight. Your response differs from the correct answer by more than 10%. Double check your calculations. s (c) Find its horizontal range Your response differs from the correct answer by more than 10%. Double check your calculations. m Need Help? .me..u A pendulum with a cord of length0950 m swings in a vertical plane (see figure). when the pendulum is in the two horizontal positions "90" and 0- , its speed is 4.90 m/s.Explanation / Answer
b)initial speed = 113m/s
angle = 45.8o
time =2.64 seconds
acceleration =34.3 m/s2
velocity of rocket after 2.64 seconds = 113+(2.64*34.3)=203.552 m/s
Distance travelled in 2.64 seconds = (113*2.64)+(0.5*34.3*2.642)=417.85 m
Horizontal distnace travelled = 417.85cos45.8=291.31m
Vertical distance travelled = 417.85sin45.8 = 299.56 m
After this, free fall starts
Horizontal velocity = 203.52cos45.8=141.89m/s
Vertical velocity= 203.52sin45.8=145.91m/s
Time taken to reach maximum height = 145.91/9.8=14.89 seconds
Maximum height reached = 145.912/(2*9.8)=1086.21 m
Maximum height reached above ground = 1086.21+299.56=1385.77 m
Time taken to fall 1385.77 seconds vertically = sqrt(1385.77*2/9.8)=16.82 seconds
Total time of flight = 2.64+14.89+16.82=34.35 seconds
c)horizontal range= 291.31+141.89*(14.89+16.82)=4790.6 m
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