Secure https://session.masteringphysics.com/myct/itemView2offset-next&assignment

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Secure https://session.masteringphysics.com/myct/itemView2offset-next&assignmentProblem; Problem 8.27: Accident Analysis Part A How fast were the enmeshed cars moving just after the collision? Two cars collide at an intersection. Car A, with a mass of 2000 kg, is going from west to east, while car B, of mass 1500 kg, is going from north to south at 140 m/s. As a result of this collision, the two cars become enmeshed and move as one In your role as an expert witness, you m/s inspect the scene and determine that, after the collision, the enmeshed cars moved at an angle of 65.0° south of east from the point of impact Submit Part B How fast was car A going just before the collision? , o @j.

Explanation / Answer

For Car A:
p=mv
p=2000*u Ns (use u as velocity so there is no confusion later on)

For Car B:
p=mv
p=1500*15
p=22500 Ns

For Enmeshed Cars:
m=1500+2000
m=3500kg
p=mv
p=3500*v Ns

Resolve Vectors:
theta=65 degrees
Adjacent (A)=2000*u
Opposite (O)=22500
Hypotenuse (H)=3500*v

A)
sin(theta)=O/H
sin(65)=22500/(3500*v)
v=22500/(3500*sin(65))
v=7.1m/s (upto 2 significant figures)
The enmeshed cars are moving at 7.1m/s.

B)
tan(theta)=O/A
tan(65)=22500/(2000*u)
u=22500/(2000*tan(65))
u=5.2m/s (upto 2 significant figures)
Car A is moving at 5.2m/s, just before the collision.

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