1) This problem looks at the electric potential due to a dipole in two different

Question

1) This problem looks at the electric potential due to a dipole in two different orientations. In both cases, Q1 is a single proton (charge-e) and Q2 is a single electron (charge =-e), where lel = 1.60 . 10-19 C. The charges are separated by a distance of 1 Angstrom (10-10 m). Use k = 8.988 x 109 N·m2/C2. As usual we are looking for the potential relative to a point that is infinitely far away (where V -o). Calculate the electric potential at point P, which is the same distance from each charge, r= 10 nm (recall 1 nm = 10-9 m). For this problem use the exact formula, not the dipole approximation. A. r=10 nm r=10nm Q1 Q2 d= 10-10 m .19 1.6x10,

Explanation / Answer

A)

potential at p

Vp = kQ1/r + kQ2/r

since Q1+Q2 =

so

Vp = 0 Volts

B)

Vp = kQ2 /(0.5d+r) + kQ1/(r-0.5d)

Vp = ke 10^10 ( 1/99.5 -1/100.5)

Vp = 1.44 x 10^-3 volts

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