NEWTON’S SECOND LAW Constant Mass data: mass (g) Force (N) acceleration (m/s 2 )
ID: 1777778 • Letter: N
Question
NEWTON’S SECOND LAW
Constant Mass data:
mass (g)
Force (N)
acceleration (m/s2)
50
0.49
0.808
60
0.59
0.939
70
0.69
1.176
80
0.79
1.3
90
0.88
1.547
100
0.98
1.672
Slope of the line: 0.58N/m/s^2
Constant Force data:
mass (g)
acceleration (m/s2)
250
1.631
500
0.8749
750
0.5874
1000
0.4508
Slope of the line: 0.392N
Questions and Conclusions:
1. According to Newton’s Second Law, F = ma, the equation has a y-intercept of zero. How does the graph of force versus acceleration for a system of constant mass support this relationship?
2. Compare the slope of the line to the total accelerating mass. Comment on the two values, and the expected relationship between them if the second law is true.
3. Newton’s Second Law, F = ma can be re-written as: a = F(1/m). How does the graph of acceleration versus inverse mass for a system of constant force support this relationship?
4. Compare the slope of the line to the constant applied force. Comment on the two values, and the expected relationship between them if the second law is true.
Please explain and asnwer questions and conclusions in depth, I mostly want to compare my own answers to see if my concpets are right.
mass (g)
Force (N)
acceleration (m/s2)
50
0.49
0.808
60
0.59
0.939
70
0.69
1.176
80
0.79
1.3
90
0.88
1.547
100
0.98
1.672
Explanation / Answer
1) Graph for force vs accleration with constant mass will a straight line passing through origin with slope of the line equal to mass of the object
2)slope of the line=mass
3)if force is constant ,graph of m vs a will be rectangular hyperbola while for a vs 1/m ,it will be a straight line
4)slope of line =force applied
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