( 14 % ) Problem 2: Consider the following circuit of three resistors (R1 , R2,

Question

( 14 % ) Problem 2: Consider the following circuit of three resistors (R1 , R2, and R3), with batteries that have emfs = 10.5 V and 35.5 V, and internal resistances ri and r2. Randomized Variables 0.5 = 10.5 V 2.5 12 1, R 6.0 1.5 0.5 E2 ©theexpertta.com 33% Part (a) Find the current 11, in amps /> 33% Part (b) Find the current 12, in amps. 33% Part (c) Find the current 13 in amps. Grade Summary Deductions Potential 13 = 4% 96% sin() | cos() | tan() | | (D-17| 8|9 cotan) asinO acosO atan) acotanOsinhO coshO tanh cotanh) Submissions Attempts remaining: 1 (4% per attempt) detailed view 4 5 6 4% 0 Degrees Radians

Explanation / Answer

Given that

E1 = 10.5 V
E2 = 35.5 V

using KCL at node a
i1 - i2 - i3 = 0 (1)

using KVL

35.5 V - (0.5 + 1.5)i3 - 6i1 = 0
6i1 + 2i3 = 35.5 V (2)

Again
10.5V - (0.5 + 2.5)i2 - 6i1 = 0
6i1 + 3i2 = 10.5V (3)

solving the equation (1),(2)&(3)
we get

i1 = 3.545 A

i2 = - 3.58 A

i3 = 7.125 A

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