1) Using the diagram, a mass spectrometer has vertical magnetic field B (magnitu
ID: 1777702 • Letter: 1
Question
1) Using the diagram, a mass spectrometer has vertical magnetic field B (magnitude 1.34 T) (in the diagram, into the page). A particle (charge 7.09x10-18 C , mass 6.63x10-26 kg) is accelerates through potential difference 2,365 V and is then shot into the spectrometer. Find d, the distance from the point of entry to where the particle hits the wall of the spectrometer, in cm.
2) A straight wire (length 24 cm, mass 407 g) lies horizontally on top of a sensitive scale. The wire is oriented so it runs north-south, and it is part of an electric circuit that includes a battery and an open switch. There is a uniform magnetic field everywhere, magnitude 45.3 T and running east to west. Suddenly the switch is closed, and current 9.1 A runs through the wire from north to south. Find the reading of the scale, a force in Newtons, after the switch is thrown.
Diagran 2Explanation / Answer
work done by potential difference W = change in KE
dV*q = (1/2)*m*v^2
v = sqrt(2*dV*q/m)
speed v = sqrt(2*2365*7.09*10^-18/(6.63*10^-26)) = 711208.5 m/s
In the magnetic field Fb = q*v*B*sintheta
theta = 90
magneitc field provides necessary centripetal force
Fc = Fb
m*v^2/r = q*v*B
r = m*v/(qB)
r = 6.63*10^-26*711208.5/(7.09*10^-18*1.34)
r = 0.005 m
d = 2r = 0.01 m = 1 cm <<<<<<<<<--ANSWER
================
2)
magnetic force on wire Fb = I*L*B*sintheta downwards
theta = 90
L = 0.24 m
B = 45.3 T
Fb = 9.1*0.24*45.3*sin90 = 98.9352 N
weight of the wire = m*g = 0.407*9.8 = 3.9886 N
reading of the scale = 98.9352+3.9886 = 103 N <><<<<--ANSWER
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