Short answer [20 points 1. (3 points) A velocity selector for ions uses perpendi

Question

Short answer [20 points 1. (3 points) A velocity selector for ions uses perpendicular electric and magnetic fields. If tield used was 800 V/m, what magnitude of magnetic field would allow selection of a velocity of 4, 000 m/s? If the electric field was removed, what would the radius of its path be in the magnetic field? (A) 0.04 T; 5.7 × 10-7 m. (B) 0.08 T, 2.9 × 10-7 m. (C) 0.16 T; 1.4 × 10-7 m. (D) 0.20 T; 1.1 × 10-7 m. placed in Calculate the magnitude of the force on a 0.03 m the wire carrying a 6.7 A current in a 0.42 T magnetic field. Also, identify 2. (3 points) A section of a horizontal wire carrying a current from +x to - is a magnetic field running +y to -y. section of the direction that the magnetie force acts on the wire? (A) 0.0017 N; +z (out of the page). (B) 0.0017 N; -z (into the page). (C) 0.084 N; +2 (out of the page). (D) 0.084 N;-2 (into the page). 3. 3 points) A series LR circuit includes a 9.0 V battery, a resistance of 5.0, and an inductance of 0.s0 H. When the switch is closed, how long does it take for the current to reach one half of its maximum value? (A) 0.11 seconds. (B) 0.16 seconds. (C) 0.23 seconds. (D) 0.55 seconds. 4. (3 points) In a series LRC circuit, the rms voltage across the resistor is 80 V, across the capacitor is 120 V, and across the inductor is 60 V. If 1.5 A is flowing in this circuit, what is the average power dissipated? (A) 40 W (B) 60 W (C) 80 W (D) 120 W. 5. (3 points) What electric field has the same energy density as a 1.0 T magnetic field? (A) 1.1 × 10-17 V/m. (B) 3.3 × 10-9 V/m. (C) 1.0 V/m. (D) 3.0 x 10 V/m. Page 7

Explanation / Answer

Problem 1)

Given,

Electric field, E = 800 V / m

Velocity, v = 4000 m/s

Magnetic field, B = E / V = 800 / 4000 = 0.2 T

Radius of path, r = mv/qB = (9.1 x 10-31 x 4000)/(1.6 x 10-19 x 0.2) = 1.1 x 10-7 m

Option (d)

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