My Notas Aak Your Teacher A basketball star covers 2.90 m hrizontally in a jump

Question

My Notas Aak Your Teacher A basketball star covers 2.90 m hrizontally in a jump to dunk the bal, His motion through space can be medeled precisely as that of a particle at his center Wmess, lis center of mass is at elevation 1.02 mwhen he leaves the fior It eaches a maximum height of 1.00 m above the loor and is at elevation 0.390 i when he touches down auain 9 Bime.ion iffers from the cuerect answer by more Uhari 10Duuble check your caloulations, s Determine his time of flight (his 'hang tim) fb) Deterrnine his hurizorital velecity at the instant of takeuff. n s Determine his vertical velocity at the instant or takeort. m19 (d) Dctemina his takacft angle above tha horizontal yma-2.7U m, and yf= U.79u m. fe) For comparison, determine the hang time or a whitetail deer making a jump with center-of-mass elevations yi-1.20 m,

Explanation / Answer

t1 = [2(1.80 - 1.02)/g] = 0.3989 sec
t2 = [2(1.80 - 0.890)/g] = 0.431 sec

a) Th = t = 0.83 sec

b) Vx = (2.90/0.83) = 3.5 m/s

c) Vy = g*t1 = 3.9 m/s

d) = arctan[Vy/Vx] = 48.1° above horizontal

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