need help with part 4 A 6.00-kg particle moves from the origin to position , hav

Question

need help with part 4

A 6.00-kg particle moves from the origin to position , having coordinates x = 5.00 m and y = 5.00 m as shown in the figure. One force on the particle is the gravitational force acting in the negative y direction. Using the equation (W = FAr cos = F·, calculate the work done by the gravitational force in going from 0 to C along the following paths. y (m) (x. y) (a) the purple path (o@O) (b) the red path (oBO) (c) the blue path (oC) (d) Your results should all be identical. Why? Part 1 of 6- Conceptualize Think about carrying a gallon of milk from the ground floor up a staircase to the third floor, and then along the corridor to your room. The work you do will be several hundred joules, and the work done by gravity in the lifting process will be a value equal in magnitude to your work but opposite in direction.

Explanation / Answer

Prt 4 of 6:

as in path OB, movement (in +y direction) is opposite to force (in -y direction)

so the angle between them is 180o

while in path BC, movement (in +x direction) is perpendicular to force (in -y direction)

so the angle between them is 90o

WoBC = WoB + WBC = (58.8 N)(5.00 m)cos(180o) + (58.8 N)(5.00 m)cos(90o)

= (58.8 x 5 x (-1) + 58.8 x 5 x 0) J

= -294 J

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