(17%) Problem 1: The figure shows an electron passing between two charged metal
ID: 1777334 • Letter: #
Question
(17%) Problem 1: The figure shows an electron passing between two charged metal plates that create a 94 N/C vertical electric field perpendicular to the electron's original horizontal velocity. (These can be used to change the electron's direction, such as in an oscilloscope.) The initial speed of the clectron is 2.7 x 106 m/s , and the horizontal distance it travels in the uniform field is 3.2 cm V. Otheexpertta.com 33% Part (a) What is its vertical deflection in m2 -.. 33% Part (b) What is the vertical component of its final velocity in m/s? 33% Part(c) At what angle does it exit in degrees? Neglect any edge effects.Explanation / Answer
a) t = 3.2 * 10-2 / 2.7 * 106 = 1.185 * 10-8 s
ay = F / m = (1.6 * 10-19 * 94)/ (9.11 * 10-31) = 1.65 * 1013
delta y = 1/2 ay t2 = 1/2 * 1.65 * 1013 * (1.185 * 10-8)2
vertical deflection = 1.158 * 10-3 m
b) vertical component vy = voy + ay t = 0 + (1.65 * 1013 * 1.185 * 10-8)
= 1.95 * 105 m/s
c) theta = tan-1 [1.95 * 105/2.7 * 106]
theta = 4.14 deg
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