Exercise 8.9 Part A A 0.160-kg hockey puck is moving on an icy, frictionless, ho

Question

Exercise 8.9 Part A A 0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. At t puc 0 the Calculate the magnitude of the velocity of the puck after a force of 25.1 N directed to the right has been applied for 6.0x102s Express your answer using two significant figures. k is moving to the right at 2.97 m/s m/s Submit My Answers Give Up Part B What is the direction of the velocity of the puck after a force of 25.1 N directed to the right has been applied for 6.0x10-2s to the right to the left Submit My Answers Gve Up Correct Part C 0 to t-6.0x10-2 S·what is the magnitude of the final velocity of the puck? If instead, a force of 12.7 N directed to the left is applied from t Express your answer using two significant figures. u= Submit My Answers ive R

Explanation / Answer

(A) change in momentum = impulse imparted

final momentum = initial momentum + impulse imparted

MVf = MVi + F.t

Vf = Vi +F.t/M

Vf = 2.97 +(25.1* 0.06) / 0.160 = 2.97 + 9.4125 = 12.3825 m/sec

(B) final velocity is toward right. as initial velocity is right and impulse imparted is also right so final velocity is toward right.

(C) Final momentum = Initial momentum + impulse

MVf = MVi - F.t (as now force is applied in opposite direction)

Vf = Vi - F.t/M

Vf = 2.97 - (12.7*0.06)/0.16 = - 1.7925 m/sec (toward left)

final magnitude of velocity is 1.7925 m/sec

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