Exercise 28.4 Part A An alpha particle (charge +2e) and an electron move in oppo

Question

Exercise 28.4 Part A An alpha particle (charge +2e) and an electron move in opposite directions from the same point, each with the speed of 2.80x105 m/s (Figure 1) Find the magnitude of the total magnetic field these charges produce at point P, which is 8.55 nm from each charge Express your answer with the appropriate units IA B ValueUnits Submit My Answers Give Up Part B Find the direction of this magnetic field to the left into the page to the right Figure 1 of 1 out of the page Submit My Answers Give Up 140° Provide Feedback Continue Electron Alpha particle

Explanation / Answer

given alpha particle

charge q = 2e

e = 1.6*10^-19 C

charge on electron = -e

speed of both electron and alpha particle, v = 2.8*10^5 m/s

A. distance from point P = 8.55 nm

as both move in opposite directions

magnetic field created by both = B

B = k*Q*vsin(theta)/r^2

theta = 140 deg

r = 8.55 nm

Q = 2e - e = e

hence

B = 10^-7*1.6*10^-19*2.8*10^5*sin(140)/(8.55*10^-9)^2 = 3.93924*10^-5 T

B. the direction of this field is out of the page ( from right hand rule)

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