Section 9.4 Newton\'s Second Law for Rotational Motion about a Fixed Axis 4. A s

Question

Section 9.4 Newton's Second Law for Rotational Motion about a Fixed Axis 4. A string is wrappe pull o ornen ofin ria 0.2kg·m rthe led with a force F, the resulting angular acceleration of the pulley is 2 rad/? radius 0.05 m and m Determine the magnitude of the force F (a) 0.4 N (b) 2 N (e) 40 N ((c))8 N 5. A certain merry-go-round is accelerated uniformly from rest and attains an angular speed of 04 rad's in the first 10 seconds. If the net applied torque is 2000 N m, what is the moment of inertia of the merry-go-round? (a) 400 kg m2 50 000 kg m2 (c) 5000 kg m2 (d) 800 kg m2 (e) This cannot be determined since the radius is not specified. 6. A string is wrapped around a pulley of radius 0.10 m and moment of inertia 0.15 kg m2. The string is pulled with a force of 12 N. What is the magnitude of the resulting angular acceleration of the pulley? (a) 18 rad/s (b) 0.13 rad/s2 (c) 80 rad/s2 (d) 0.055 rad/s? (e)8.0 rad/s2 tion 9.5 Rotational Work and Energy 7. A hollow cylinder of mass M and radius R rolls down an inclined plane. A block of mass M slides down an identical inclined plane. Complete the following statement: If both objects are released at the same time, (a) the cylinder will reach the bottom first. the block will reach the bottom first. the block will reach the bottom with the greater kinetic energy (d) the cylinder will reach the bottom with the greater kinetic energy (e) both the block and the cylinder will reach the bottom at the same time

Explanation / Answer

The torque due to the force will be

=F.R

And this torque will be equal to

I(alpha)

I is the moment of inertia and alpha is the angular acceleration

So,

F=I(alpha)/R

=0.2*2/0.05

F=8N

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