the spring inside the toy has spring constant of 220 N/m. the toy is compressed
ID: 1776706 • Letter: T
Question
the spring inside the toy has spring constant of 220 N/m. the toy is compressed by 2.5 cm. the toy is held in static equilibrium for a short time by atmospheric forces acting upon the suction cup attached to the toys upper half as it is pressed against its lower half. once air leaks back into the suction cup, the spring force can launch the toy into the air. the mass of the toy is 15 grams. Use the equilibrium (uncompressed) position of the toy as the zero point for potential energy.A. Find the launch speed of the toy B. Find the maximum altitude reached by the toy the spring inside the toy has spring constant of 220 N/m. the toy is compressed by 2.5 cm. the toy is held in static equilibrium for a short time by atmospheric forces acting upon the suction cup attached to the toys upper half as it is pressed against its lower half. once air leaks back into the suction cup, the spring force can launch the toy into the air. the mass of the toy is 15 grams. Use the equilibrium (uncompressed) position of the toy as the zero point for potential energy.
A. Find the launch speed of the toy B. Find the maximum altitude reached by the toy the spring inside the toy has spring constant of 220 N/m. the toy is compressed by 2.5 cm. the toy is held in static equilibrium for a short time by atmospheric forces acting upon the suction cup attached to the toys upper half as it is pressed against its lower half. once air leaks back into the suction cup, the spring force can launch the toy into the air. the mass of the toy is 15 grams. Use the equilibrium (uncompressed) position of the toy as the zero point for potential energy.
A. Find the launch speed of the toy B. Find the maximum altitude reached by the toy
Explanation / Answer
(A) Applying energy conservation,
k x^2 / 2 = m v^2 / 2
220 (0.025^2) = (0.015)(v^2)
v = 2.14 m/s ....Ans
(B) m v^2 /2 = m gh
h = v^2/ 2 g = 0.233 m or 23.3 cm
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