Fall 2017 November 7, 2017 Nov D.P. Weygand Physics 227/232 ODU Name 9) A conduc

Question

Fall 2017 November 7, 2017 Nov D.P. Weygand Physics 227/232 ODU Name 9) A conducting bar moves along frictionless conducting rails connected to a 40042 resistor as shown in the figure. The length of the bar is 1.60 m and a uniform magnetic field of 2.20 T is applied perpendicular to the paper pointing outward, as shown (a) What is the applied force required to move the bar to the right with a constant speed of 6.00 m/s? (b) At what rate is energy dissipated in the 4.00 resistor? D.P. Weygand November 7, 2017 Fall 2017 4.00 1.60 m applied Magnetic field is outward ()

Explanation / Answer

a)

We know that induced Emf in a rod, moving with velocity V is

BVL where B is the magnetic field and L is the length of the rod

So here induced EMF will be

2.2*1.6*6

=21.12

Now force on a conductor with current I is

BIL

so I in the rod will be

I=21.12/4

=5.28A

So force will be

2.2*5.28*1.6

F=18.5856N

this should be the applied force in order to move the rod with zero acceleration.

b)

Now, current in the resistor is

5.28A

So power dissipated will be

I2R

so

5.282*4

=111.5136W

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