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In Part 1, calculate the percentage of momentum and kinetic energy “lost during

ID: 1776584 • Letter: I

Question

In Part 1, calculate the percentage of momentum and kinetic energy “lost during the collision.What are the possible sources that causes the loss? Where did the lost energy go?

Trial

M1[kg]

M2[kg]

V1[m/s]

V1'[m/s]

V2[m/s]

V2'[m/s]

1

0.1779kg

0.1793kg

0.33 m/s

0 m/s

0 m/s

0.3188 m/s

2

0.1779kg

0.2793kg

0.5975 m/s

0.1090 m/s

0 m/s

0.298 m/s

3

0.2779kg

0.1793kg

0.4598m/s

0m/s

0 m/s

0.5366 m/s

Trial

M1[kg]

M2[kg]

V1[m/s]

V1'[m/s]

V2[m/s]

V2'[m/s]

1

0.1779kg

0.1793kg

0.33 m/s

0 m/s

0 m/s

0.3188 m/s

2

0.1779kg

0.2793kg

0.5975 m/s

0.1090 m/s

0 m/s

0.298 m/s

3

0.2779kg

0.1793kg

0.4598m/s

0m/s

0 m/s

0.5366 m/s

Explanation / Answer

I am doing calculations for Trial 1.

initial momentum =( 0.1779) (0.33) +0.1793 (0) =0.058707 kg m/s

final momentum = (0,1779) (0) +(0.1793)(0.3188) =0.05716084

% loss in momentum= ( 0.058707- 0.05716084) / 0.058707 x 100= 2.633 % apprx

Initial KE = 1/2 ( 0.1779 ) (0.33^2) =0.009686655

Final KE = 1/2 (0,1793) (0,3188^2) =0.009111437896

% loss in KE =( 0.009686655- 0.009111437896)/  0.009686655) x 100= 5.94 %

sources= friction, sound produced during collision, heat produced in collision.

KE gets converted to other forms of energies( like heat and sound)

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