1) The refractive index of a transparent material can be determined by measuring

Question

1) The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If c= 41.1° what is the index of refraction of the material?

2) A light ray strikes this material (from air) at an angle of 32.6° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees).

3) Calculate the angle of the refracted ray (in degrees).

4) Assume now that the light ray exits the material. It strikes the material-air boundary at an angle of 32.6° with respect to the normal. What is the angle of the refracted ray?

Explanation / Answer

here,

1)

thetac = 41.1 degree

let the index of refraction of the material be n

the critical angle , theta = arcsin(1/n)

sin(41.1) = (1/n)

solving for n

n = 1.52

the index of refraction of the material is 1.52

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