thanks! Class Management Help Practice 8 Begin Date: 9/13/2017 00:00 AM Due Date

Question

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Class Management Help Practice 8 Begin Date: 9/13/2017 00:00 AM Due Date: 11/7/2017 11:59:00 PM End Date: 12/4/2017 11:59:00 PM A 52 kg and a 82 kg skydiver jump from an airplane at an altitude of 6000 m, both falling in the (14%) Problem 6: diving/headfirst position. Assume their surface area is 0.105 m2 and the drag coefficient is 0.70. Randomized Variables m1 = 52 kg m2 = 82 kg A 0.105 m 50% Part (a) How long will it take for the first skydiver to reach the ground in seconds assuming the time to reach terminal velocity is small and the density of the air is a constant 1.21 kg/m3)? 50% Part (b) How long will it take for the second skydiv er to reach the ground in seconds (assuming the time to reach terminal velocity is small)? Grade Summary Deductions 100% Potential 0% sin cos cotan asin acosO atan acotan sinh0 cosh tancotanho tan() | | ( Submissions Attempts remaining: 10 (1% per attempt) detailed view 4 5 6 0 e DegreesRadians Submit Hint I give up!

Explanation / Answer

terminal velocity v = (2mg / AC)

v = (2*m*9.8m/s² / 1.21kg/m³*0.105m²*0.7) = (m * 220.2m²/kg·s²)

1) v = (52kg*220.2m²/kg·s²) = 107 m/s

and t = d / v = 6000m / 107m/s = 56 s

2) v = (82kg*220.2m²/kg·s²) = 134.37 m/s

and t = 6000m / 134.37m/s = 44.65 s

Hope this helps!

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