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(b) In reality, the angular speed of a baggage carousel does not change. Therefo

ID: 1776270 • Letter: #

Question

(b) In reality, the angular speed of a baggage carousel does not change. Therefore, what must be the external torque acting on the system if ten bags are dropped each minute?

IT IS NOT 1.262

2- An electric motor can accelerate a Ferris wheel of moment of inertia I = 18500 kg·m2 from rest to 9.9 rev/min in 12.0 s. When the motor is turned off, friction causes the wheel to slow down from 9.9 to 7.9 rev/min in 10.0 s. (a) Determine the torque generated by the motor to bring the wheel to 9.9 rev/min. IT IS NOT 1590 or 1598

Explanation / Answer

1)since bags reloded vertically they do not add to the tangential momentum of the carousel.

angular momentum=Iw unit=MR^2

for each bag i=29.0*1.80^2=93.96kg.m^2

for 10 bage is 93.96kg.m^2

applying law of conservation of momentum and assuming final angular velocity.

momentum before=1500*0.29

=435kgm^2/s

momentum after=1500*969=1453

=1453=435

=1453/435

=3.340rad/sec.

2)angular acceleration=a=[9.9rpm*2*3.14]/[12*60]

=0.086rad/s^2

torque=i*a=18500*0.086

=1591N*M

inital energy=(1/2)*i*w^2=w=9.9

=77966.9rad/sec