ALL PARTS (11%) Problem 2: Linearly polarized light is transmitted through two p

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(11%) Problem 2: Linearly polarized light is transmitted through two polarizers as shown in the figure. The light is polarized in the y direction. The axis of the first polarizer is at ,-32° to the y direction. The axis of the second polarizer is at ,- 54° to the y direction. The intensity of the initial beam of polarized light is lo Polarized Light ©theexpertta.com 25% Part (a) Express the intensity of the light after it passes through the first polarizer, 11 , in terms of 10, and | Grade Summary Deductions Potential 0% 100% 7 8 9 cos() cos(0) sin(21)| sin(01) | cos(21)| | cos(81) | sin() cos() sin() sin(0) Submissions Attempts remaining: Z (0% per attempt) detailed view 0 END 0 BACKSPACE DEL CLEAR Submit Hint I give up! Hints: 2% deduction per hint. Hints remaining: 1 Feedback: 2% deduction per feedback - 25% Part (b) Express the intensity of the light after it passes through the second polarizer, 12, in terms of 11, 12, where 12 2-01 - 25% Part (c) If is the fraction of the light transmitted through the two polarizers, express in terms of ! and 12-where 12-82- 25% Part (d) Solve for the numerical value off.

Explanation / Answer

here,

initial intensity is I0

a)

for first polarizer

I1 = I0 * ( cos(theta1))^2

b)

for the seccond polarizer ,

I2 = I1 * ( cos(theta2))^2

I2 = I0 * ( cos(theta1))^2 * ( cos(theta2))^2

c)

fraction of light transmitted , f = I2/I0

f = ( cos(theta1))^2 * ( cos(theta2))^2

d)

theta1 = 32 degree

theta2 = 54 degree

f = ( cos(theta1))^2 * ( cos(theta2))^2

f = ( cos(32))^2 * ( cos(54))^2 = 0.25

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