previous 16 of 16 I return to assignment Problem 31.28 Part A What is the electr

Question

previous 16 of 16 I return to assignment Problem 31.28 Part A What is the electric field strength at the position of the electron in (Figure 1)? Assume that B 0.19 T and F 2.8x10-13 N Express your answer with the appropriate units E-Value UUnits Submit My Answers Give Up Figure 1 ¢ of 1 Part B What is the electric field direction at the position of the electron? 30° A2p o , measured clockwise from the positive in ry plane axis Moving out of page at 1.0 × 107 m/s Submit My Answers Give Up Continue

Explanation / Answer

Net force is Fnet = Fe + Fm

Electric force is Fe = Fnet - Fm

magnetic force is Fm = q*v*B*sin(theta)

Fm = (1.6*10^-19*1*10^7*0.19*sin(90)

Fm = 3.04*10^-13 N

Fe = Fnet - Fm

magnitude of Fe is sqrt((3.04*10^-13)^2+(2.8*10^-13)^2+(2*2.8*3.04*10^-26*cos(60)))

Fe = 5.06*10^-13 N

direction is tehta = tan^(-1)[3.04*sin(60)/(4+(3.04*cos(60)))] = 25.5 deg

required angle 30+25.5 = 55.5 deg

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