please help TART WRITING 28 A A sled is pulled up to the top of a hill. The sket
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TART WRITING 28 A A sled is pulled up to the top of a hill. The sketsh above indicates the shape of the hill. At the top of the hill the sled is released from rest and allowed to ccast down the hill. A: the bottom of the hill the sled has ase a kinetic energy E (the energy due to the and air resistance are so small they can be ig sled's motion). Answer the following questions. In every case fricrion 4. The sled is pulled of the sled the up a steeper hill of the same height as the hill described above. How will the velocity at the bottom of the hill (after it has slid down) compare to that of the sled at the botom of the original hill? Choose the best answer below A-The speed at the bottom is greater for the steeper hill. B. The C. The s e speed at the bottom is the same for both hills. is not enough information given to say which speed at the bottom is faster. J. None of these descriptions is corect. 45. Compare the kinetic energy (energy of motion) of the sled at the bottom for the original hill and the steeper hill in the previous problerm. Choose the best answer below A. The kinetic energy of the sled at the bottom is greater for the steeper hill. B, The kinetic energy of the sled at the bottom is the same for both hills C. The kinetic energy at the bottom is greater for the original hill. D. There is not enough information given to say which kinetic energy is greater J. None of these descriptions is correct. 46. The sled is pulled up a higher hill that is less steep than the original hill described before question 44 How does the speed of the sled at the bottom of the hill (after it has slid down) compare to that of the sled at the bottom of the original hill? A. The speed at the bottom is greater for the higher but less steep hill than for the original. B. The speed at the botom is the same for both hills. C. The speed at the bottom is greater for the original hill. D. There is not enough information given to say which speed at the bottom is faster. J. None of these descriptions is correct. 46a. Describe in words your reasoning in reaching your answer to question 46, (Answer on the answer sheet and use as much space as of the hill after it 47. For the higher hill that is less steep, how does the kinetic has slid down compare to that of the original hill? of the sled at the A. The kinetic energy of the sled at the bottom is greater for the higher but less steep hill. B. The kinetic energy of the sled at the bottom is the same for both hills. C. The kinetic energy at the bottom is greater for the original hil D. There is not enough information given to say which kinetic energy is greater. J. None of these descriptions is correct Tools for Scientific Thinking, CSMT, Tufts U. Force and Moton Conceptual Evaluation 5/99 T-7 Force and Motion 1989-99 R.K Thomton & D. SokoloifExplanation / Answer
44) Speed of the sled at the bottom for both the hills will be same. We can find it using third equation of motion.
v^2 = 2.a.s, (u = 0). acceleration a will be more for steeper hill but it will travell less distance compare to the original hill. Term a.s comes out to be constant for both the hills and that is h.g. As for hill one a = g.sin(theta1) and s = h/(sin(theta1)). Similarly for second hill a = g.sin(theta2) and s = h/(sin(theta2))
So B option is correct.
45) B. Kinetic energy of the sled at the bottom will be same for both the hills as speed at the bottom is same.
46) A. Using the reasoning as given in answer of que no 44 above, speed of the sled at the bottom for the higher but less steep hill is greater.
46a) Speed of the sled at the bottom for the higher but less steep hill will be greater. Because sled sliding from higher hill have more potential energy initially which will be converting into kinetic energy compare to other one. we can show it using third equation of motion also.
v^2 = 2.a.s, (u = 0).
For hill one (which has more hieght), a1 = g.sin(theta1) and s1 = h1/(sin(theta1)). sin(theta1) will be h1/s1. From here we find that a1.s1 = h1.g Similarly for second hill (original one) a2 = g.sin(theta2) and s2 = h/(sin(theta2)) and sin(theta2) = h/s2. a2.s2 = h.g . Now as h1 is greater than h, velocity v1 will be more hence speed.
47) A. The kinetic energy of the sled at the bottom is greater for higher but less steep hill. It can be concluded easily as for higher hill velocity at the bottom will be more compare to other one.
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