Problem 2: Two birds are flying in two different directions. One bird with mass
ID: 1775563 • Letter: P
Question
Problem 2: Two birds are flying in two different directions. One bird with mass mi = 200 g is flying north east with a velocity denoted by v, = (3,4) m/s. The other bird of mass m2 = 150 g is flying south with velocity v2 = (0,-6) m/s. Find the total momentum p of the two bird system. Also find the magnitude of the total momentum (p) and the direction(6). Problem 3: An astronaut of mass M 120 kg is standing stil in space and throws a ball. The mass of the ball is m-200 g. The final velocity of the ball after being thrown is =-10 m/s. Use conservation of momentum to find the final velocity (va) of the astronaut. Problem 4: A truck of mass M-10,000 kg collides againt a car of mass m = 2000 kg. The car was originally parked and stationary. The truck had a speed of 30 m/s. After the collision the car is stuck to the truck. We assume that the truck driver had pressed on the breaks and was sliding on the road. It is also assumed that the collision interval is short so that the frictional forces can be neglected over that short period of time. What is the final speed of the truck(and car) right after the collision? Problem 5: A glider moves towards another glider on a frictionless track. Glider one has a mass of mi = 100 g and a velocity of U-8 m/s. Glider two has a massExplanation / Answer
problem 2
m1 = 200g = 0.2 kg
m2 = 150 g = 0.15 kg
v1 = (3 , 4)
v2 = (0 , -6)
total momentum Ptotal = m1*v1 + m2*v2
Ptotal = 0.2*(3 , 4) + 0.15*(0 , -6)
Ptotal = (0.6 , 0.8) + (0 , -0.9)
Ptotal = (0.6 +0 , 0.8 - 0.9)
Ptotal = (0.6 , -0.1)
magnitude = sqrt(0.6^2+0.1^2) = 0.61 kg m/s <<<------------ANSWER
direction , theta = tan^-1(-0.1/0.6) = 9.46 degrees south of east
===================
Problem 3
from momentum conservation
momentum before throwing = momentum after throwing
0 = M*va + m*vb
0 = (120*va) - (0.2*10)
va = 0.012 m/s
========================
Problem 4
momentum before collision = momentum after collision
M*V + m*v = (M+m)*vf
(10000*30) + (m*0) = (10000 + 2000)vf
vf = 25 m/s
========================
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.