#8 Momentum: Inelastic ID Cllisions wo 2.4 kilograms pieces of putty collide and
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#8 Momentum: Inelastic ID Cllisions wo 2.4 kilograms pieces of putty collide and stick together, yielding a single 4.8 kilograu pieee of putty has a velocity of 4.5 m/s to the right, and the second piece lt of45 ms to the left. What is the velocity of the system after the of putty has a ision? O A. 4.5 m/s (to the right) 0 B. 2.25 m/s (to the left) ° C. 2.25 m/s (to the right) 0 D. 0.0 m/s #9 Momentum: Inelastic ID Collisions How much kinetie 27 energy is lost over the course of the collision described in question A. 0.0 Joules O B. 24.3 Joules ° C. 48.6 Joules 0 D. 686 Joules s hass (mass 1) moves to the right with a speed of 2.50 m/s and collides with a is elastic, what are the velocities 10 Elastic Collisions in One Dimension 1.30 kg mass (mass 1) stationary 1.30 kg mass (mass 2). Assuming the collision of the first and secoond masses following the collision? mass 2: 1.25 m/s to the right mass 2: 2.50 m/s to the right mass 2: 1.25 m/s to the right mass 2: 0.50 m/s to the right A.mas l: 1.25 m/s to the right O B. mass 1: 0.00 m/s 0 C, mass 1: 1.25 m/s to the left 0 D. mass 1: 2.00 m/s to the right #11 Conservation of Moment urn in Two Dimensions Two masses collide in a completely inelastic collision. . The first mass my2.4 kg has an initial velocity i (1.3 m/s,2.1 m/s). . The second mass m - 1.4 kg has an initial velocity t (-1.7 m/s, 1.8 m/s). Assume that following the collision my and ma have each combined into a single large mass M with a velocity t. What is the value of the combined mass M? and m2 have O A. 3.8 kg O B. 5.3 kg O C 7.8 kg O D. 10.2 kgExplanation / Answer
8. Applying momentum conservation,
(2.4 x 4.5) + (2.4 x -4.5) = 4.8 v
v = 0
9. Ki = 2 (2.4 x 4.5^2 / 2) =48.6 J
Kf = 0
Klost = Ki - Kf = 48.6 J ..Ans
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