work Problem 10.32 Enhanced- with Feedback Problem 10.32- Enhanced-with Feedback

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work Problem 10.32 Enhanced- with Feedback Problem 10.32- Enhanced-with Feedback Part A A 1400 kg car is approaching the hill shown in (Eigure Can the car make it to the top of the hill by coasting? 1) at 13 m/s when it suddenly runs out of gas. Neglect any friction You may want to review(Lages 300-304 No, the car wll not reach the top of the hil Yes, the car will stop exacty on the top of the hil. Yes, he car wil passmetop ofthe hil and wa continue to move down More information is needed · My Answers Give Up Correct Here we leam to apply the energy conservation law Part B What is the car's ed after coasting down the other side? Express your answer to two significant figures and include the appropriate units Value Units My Answers Give Up

Explanation / Answer

a) According to law of conservation of energy, the car will pass the top of the hill and will continue to move down(neglecting friction)

b) Kinetic Energy of the car is

KE = (1/2)mv2 = 0.50(1400)(13)2 = 118300 J

Weight of the car is 1400*9.8 = 13720 N

energy required to get to the top is 13720*5 = 68600 J

so it can get to the top with 118300 – 68600 = 49700 J left.

It has potential energy at the top of 13720*10 = 137200 J

so it's total energy is 137200 + 49700 = 186900 J

If this is converted into speed, then:

KE = 0.5*mv2

186900 = 0.5*(1400)v2

V = 16.34 m/s

assuming friction in not in force.

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