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(14%) Problem 3: A sandwich board advertising sign is constructed as shown in th

ID: 1775047 • Letter: #

Question

(14%) Problem 3: A sandwich board advertising sign is constructed as shown in the figure, where "CG" indicates the center of gravity for each board. The sign's mass is 8.1 kg Hinge 0.50m Chain 1.30m CG CG Uniform board (cG at center) 1.10 m ©theexpertta.com 50% Part (a) Calculate the tension, in newtons. in the chain assuming no friction between the legs and the sidewalk. Grade Summary Deductions Potential T= 33.58 4% 96% sin) 789 HOME cos tan( ) Submissions Attempts remaining: 2 cotan ašin acos % per attempt) detailed view atan()acotan()sinh() cosh) tanh cotanh 4% END Degrees Radians O BACKACE DF. CLEA Submit Hint I give up! Hints: 4% deduction per hint. Hints remaining: 4 Feedback: 5% deduction per feedback.

Explanation / Answer

Here ,

for the tension T in the cable

let the normal force on each is N

as N =m * g

for the angle of the ladder with vertical is theta

sin(theta) = (1.1/2 * 1.30)

theta = 25 degree

Now, balancing the torque about the hinge on one ladder

- mg * 0.55 + mg * (1.1/4) + T * 0.50 = 0

solving for T

T = 0.55 mg = .55 * 8.1 * 9.8

T = 43.7 N

the tension in the cable is 43.7 N