. Spring! 7-123-Momer © A Car With A Mass Of 9EX mg to kg-Google Searc Cooper x
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. Spring! 7-123-Momer © A Car With A Mass Of 9EX mg to kg-Google Searc Cooper x × × · Secure | https://wwww.webassign.net/web/Student/Assignment-Responses/last?depz16554942 6. -2 points 16 8.3.WA.020 My N A car with a mass of 980 kg is initially traveling east toward an intersection with a speed of Ve 18.9 m/s and a 1500 kg pickup is traveling north toward the same intersection. The car and truck collide at the intersection and stick together. After the collision, the wreckage (car and truck) moves off in a direction of 45.0° above the x-axis. Determine the initial speed of the truck and the final speed of the wreckage. initial speed of the truck final speed of the wreckage m/s Additional Materials Reading 9:36 PM O Type here to search 41)) 11/3/2017 ^Explanation / Answer
If the wreckage (car and truck) 980kg +1500kg = 2480 kg. m1 + m2 = m.
and then, if wreckage is the final speed of v. Then v1 final = v2 final = v final.
m1 * v1x + m2 * v2x = m*v * cos45
since car (v1) is moving eastward it has x component. And because truck is moving to the noth it has not x component.
v2x = 0 => m2* v2x =0.
m1*v1x = m*v * cos 45
Cos 45 = 0.7071067
(980 kg) * (18.9 m/s) = (2480 kg) * v * 0.7071067
10.56212 m/s = v.
Final speed of wreckage is 10.56212 m/s/
y component:
Since car is moving eastward it has not y component, then v1y = 0. But truck is moving to the north it has y component:
m2 * v2y = m*v * sin45
(1500kg) * v2y = (2480 kg) * (10.56212m/s) * 0.7071067
v2y = 12.248 m/s.
Truck had 12.348 m/s velocity until collision.
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