18. [ipt] The curve in the energy diagram shows the potential energy, tx ofa par

Question

18. [ipt] The curve in the energy diagram shows the potential energy, tx ofa particle as a function of its position, x. The total energy ofthe particle, E, is constant (the hcrizontal line above the cuve). The grid is divided into squares that are S J high and 1 m wide 7 The graph of Uis labelled for 8 positions of the particle Answer True, False, or Cannot tell to each of the statements below; e.g., if the first statement is true and the rest, cannot tell, enter TCCccC. t. If the particle is located slightly to the right of position 2, the force on the particle is dimected to the right ii. The net force on the particle is zero when it is located at position 2, this is a point of stable equilibrium. iii. The force on the particle at position1 is directed to the right. iv. The slope of Uix) is zero when the particle is located at pcsition 7, so the force on the particle is zero v. The net force on the particle is a maximum when is at pesition 2. vi. A point of stable equilibrium is one in which small deviations from the equilibrium point will create a force that accelerates the particle away from the equilibrium point

Explanation / Answer

18. F = - dU/dx

so force is negative of slope of U vs x curve.

i. slope - +ve => force - -ve to the left

False

ii. at 2, slope is zero so F = 0

true

iii. at 1 , slope - -ve so F -> +ve so to the right

True

iv. False (slope at 7 is not zero)

v. at 2, F = 0 so false

vi. False, this is the condition for the unstable eq.

Ans: FTTFFF

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.