b) Now we use a break to uniformly slow down the s cylinder rotation. IE it take
ID: 1774309 • Letter: B
Question
b) Now we use a break to uniformly slow down the s cylinder rotation. IE it takes 2.0 min to slow down this ate the angular acceleration of the wheel daring this period phere to 200re rewmin, calculate If the same deceleration continues,detemine the angular velocity of the wheel 10.0 s later (10.0 s after i reaches 200 n) c) d) Howmany turns does the cylinder make during this 10.0 s time? e) Assume this deceleration is done by a applying a constant friction force, such as pushing a rough object (shown as A in the figure) in the belly. If against the sphere -0.8 between A and cylinder, calculate how hard A is pushedExplanation / Answer
a)
R=0.20m, M=10.0kg,wi=0rads, wf=600rev/min= (600*2rad)/(60s)=(10*2*3.14)rad/s = 62.83rad/s
KE=KEf-KEi=1/2Iwf^2=1/2*(1/2MR^2*(wf^2) = 1/4MR^2wf^2=1/4*10.0*0.20^2*62.83^2 = 394.76 J
b)
= w/t = (wf-wi)/t = (200rev/min-600rev.min)/2min = -200rev/min^2 = - 0.35rad/^2
c)
wf’=wi’+ *t = (200rev/min) -0.35rad/s*10.0s = 20.94rad/s – 3.5 rad/sn= 17.44 rad/s
d)
=wi’*t +1/2**t^2 = 20.94*10 -1/2*0.35*10^2 = 191.9 rad = (191.9/(2)) = 30.54 rev
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