Your answer is partially correct. Try again. A uniform spherical shell of mass M

Question

Your answer is partially correct. Try again. A uniform spherical shell of mass M-11.0 kg and radius R 0.810 m can rotate about a vertical axis on frictionless bearings (see the figure). A massless cord passes around the equator of the shell, over a pulley of rotational inertia 1 0.0930 kg-m2 and radius r = 0.0870 m and is attached to a small object of mass m 3.30 kg. There is no friction on the pulley's axle; the cord does not slip on the pulley, what is the speed of the object when it has fallen a distance 1.01 m after being released from rest? Use energy considerations M, R Num 1.512 UnitsT m/s the tolerance is +/-296

Explanation / Answer

Ishell = moment of inertia of shell = 2 mR2

using conservation of energy

Potential energy of hanging block = Kinetic energy of hanging block + KE of pulley + Rotational KE of spherical shell

mgh = (0.5) m v2 + (0.5) I w2 + (0.5) Ishell w2

mgh = (0.5) m v2 + (0.5) I (v/r)2 + (0.5) (2/3) (MR2) (v/R)2

mgh = (0.5) m v2 + (0.5) I (v/r)2 + (0.5) (2/3) (Mv2)

(3.3) (9.8) (1.01) = ((0.5) (3.3) + (0.5) (0.093) (1/0.087)2 + (0.5) (2/3) (11)) v2

v = 1.7 m/s

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.