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9) Force-8 x4-2 x, find the work in mks units done by the force for a distance o

ID: 1774239 • Letter: 9

Question

9) Force-8 x4-2 x, find the work in mks units done by the force for a distance of x-2 to x-8. A) 2400J B) 1024000 J C) 1000J D) 52318J E) 3200 J To, A 1700 kg automobile moving at a maximum speed of 26 m/s on a level circular track of radius of 115 m. What is the coefficient of friction? A) 0.384 B) 0.64515 C) 0.9775 D) 0.5998 E) 1.326 I l. A 17 kg block rests on a 3501 nclined friction less surface and is attached by a light string to a 18 kg hanging mass where the string passes over a massless frictionless pulley. If g = 9.8 m/s, what is the tension in the connecting string? A) 306 N B) 166.6 N C) 33.1N D) 134.8N E) 91.8N

Explanation / Answer

10) umg = mv2/R

=> u = v2/gR = 26 x 26/(115 x 9.8) = 0.5998

11) 18g = 18a + T

and T = 17gsin35 + 17a

=> T = 17gsin35 + 17(18g - T)/18

=> 35T/18 = 17gsin35 + 17g

=> T = (17 x 18 x 9.8)(1+sin35)/35 = 134.8 N

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