J. A straight conductor wire loops around in a complete circle of radius R secti
ID: 1774226 • Letter: J
Question
J. A straight conductor wire loops around in a complete circle of radius R sections, as shown. This wire lies in the plane of the paper an 20.0 cm, between its two straight long d carries a current l = 60.0 A. A second straight n in the same plane which carries a current I' located a distance d-12 cm from the loop center, at some angle, as shown. The I and I' current carrying wires are insulated from one another. a) What is the magnetic field vector at the center of the loop due toI What should be the value and direction of I', such that the magnetic field at the center of the loop vanishes? b)Explanation / Answer
a] Magnetic field due to i = B due to straight wire + B due to circular portion
= u0 i /2R + u0i/[2pi R]
= 2pi*10^-7*60/0.20 + 2e-7*60/0.20
= 0.0002485 T into the page answer
b] For vanishing, magnetic field due to second wire should be 0.0002485 T out of the page, so current should be towards left.
u0 i'/2pid = 0.0002485
2e-7*i'/0.12 = 0.0002485
i' = 0.0002485*0.12/2e-7
= 149.1 A towards left answer
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.