1.10 kg object slides to the right on a surface having a coefficient of kinetic
ID: 1774201 • Letter: 1
Question
1.10 kg object slides to the right on a surface having a coefficient of kinetic friction 0.250 (Fig. P7.54). The object has a speed of vi = 3.10 m/s when it makes contact with a light spring that has a force constant of 50.0 N/m. The object comes to rest after the spring has been compressed a distance d. The object is then forced toward the left by the spring and continues to move in that direction beyond the spring's unstretched position. The object finally comes to rest a distance D to the left of the unstretched spring.
(a) Find the distance of compression d.. m
(b) Find the speed v at the unstretched position when the object is moving to the left. m/s
(c) Find the distance D where the object comes to rest. m
Please explain as much as possible!
Explanation / Answer
a] By conservation of energy
0.5 m vi^2 = 0.5kd^2 + umgd
0.5*1.1*3.1^2 = 0.5*50*d^2 + 0.25*1.1*9.8d
d = 0.409 m answer
b] By conservation of energy
0.5 mv^2 = 0.5*1.1*3.1^2 - 2*0.25*1.1*9.8* 0.409
dividing by 0.5m, and taking square root,
v = sqrt(3.1^2 - 9.8* 0.409)
= 2.367 m/s answer
c] again By conservation of energy
0.5 mv^2 = umgD
D = 0.5 mv^2/[umg] = 0.5*2.367^2/(0.25*9.8) = 1.143 m answer
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