last hw problem that im struggling with to find the right temps and Q. please he
ID: 1773729 • Letter: L
Question
last hw problem that im struggling with to find the right temps and Q. please help me understand this material better and acquire the orrect solution. thank you!!
Exercise 19.13 MasteringPhysi Tmn 241.4209.6734 The pV diagram in the figure (Fiqure 1) shows a process abe involving 0.950 mol of an ideal gas. My Courses Submit My Answers Givr Un Course Home Incorrect; Try Again; 13 attempts remaining; no points deducted Scores e Text Dynamic Study Modules Study Area Course Materials Term 1: Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant igures. Term 2: Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures Part B How much work was done by or on the gas in this process? W 2.10104 J Figure 1 of 1 Submit My Answo Give Up p(Pa × 105) 8.0 6.0 4.0 2.0 Correct Part C How much heat had to be put in during the process to increase the internal energy of the gas by 1.60 1041? -V(m2) 0 0.020 0.060 0.040 0.080Explanation / Answer
As you want to understand the concept and acquire the solution by yourself, It's a good practise to understand.
1. For an Ideal gas, We have an equation of state which is given as
PV = nRT
where, P - Pressure in Pascals, V - Volume in cubic meters, n - moles, R - gas constant (8.314), T - Temperature
As we are having a PV diagram and moles, we can easily calculate temperature at each point by modifying the equation.
T = PV / nR
For example, at point a, we have P = 2 * 105 Pa and V = 0.010 m3 , n = 0.95 which is close to 1. R = 8.314
Then, T = 2 * 105 * 0.010 / 0.95 * 8.314 = 254 K ( approximately)
Proceed in the same manner for point b and c.
2. The word done is equal to area under the curve.
3. Heat added can be calculated by
Q = m*Cp*(Tfinal - Tinitial)
here, Cp is the specific heat at constant pressure which is (5/2R) If not given take gas as monoatomic.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.