(696) Problem 12: Two coils are placed close together in a physics lab to demons
ID: 1773726 • Letter: #
Question
(696) Problem 12: Two coils are placed close together in a physics lab to demonstrate Faraday's law of induction. A current of 4.5 A in one is switched off in 2.75 ms, inducing an average 7 V emf in the other. What is their mutual inductance? Randomized Variables t= 2.75 ms I=45 A What is their mutual inductance in mH? Grade S Deductio Potential cosO asin) atanO)acotanO) sinh) coshOtah cotanh0 Degrees O Radians Submiss Attempts (0%per detailed sin acos() 0 END BACKSPACE DEL CLEAR Submit Hint I give up! Hints: 2% deduction per hint. Hints remaining: 3 Feedback: 2% deduction per feedback.Explanation / Answer
current = 4.5 A
time = 2.75 ms
emf = 7 V
emf = -mutual inductance * change in current / time
7 = -mutual inductance * 4.5 / (2.75 * 10^-3)
mutual inductance = - 4.278 mH
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