1. Consider a skydiver falling from an airplane. Over this distance the weight o
ID: 1773490 • Letter: 1
Question
1. Consider a skydiver falling from an airplane. Over this distance the weight of the skydiver is essentially constant. As the skydiver falls and before the chute opens, the force of air resistance on the skydiver behaves how?
a. Also stays constant.
b. Gets larger the faster the diver moves.
c. Becomes smaller the faster the diver moves.
d. Is not a significant factor in the motion.
2.When terminal velocity is achieved, what must be true?
a. The drag coefficient must equal the weight.
b The terminal velocity must equal the weight.
c.The drag force must equal the weight.
d. None
3.According to your book, the drag force depends on velocity how?
a. Fdrag=A*v
b. Fdrag=A*v^2
c. Fdrag=A*v^3
d. None
For a skydiver, which of the variables below changes significantly after the chute opens, thus dramatically reducing terminal velocity to a safe value
a. Area cross section of object in the direction of motion
b. Density of the air
c. Viscosity of the air
d. None.
a. Also stays constant.
b. Gets larger the faster the diver moves.
c. Becomes smaller the faster the diver moves.
d. Is not a significant factor in the motion.
2.When terminal velocity is achieved, what must be true?
a. The drag coefficient must equal the weight.
b The terminal velocity must equal the weight.
c.The drag force must equal the weight.
d. None
3.According to your book, the drag force depends on velocity how?
a. Fdrag=A*v
b. Fdrag=A*v^2
c. Fdrag=A*v^3
d. None
For a skydiver, which of the variables below changes significantly after the chute opens, thus dramatically reducing terminal velocity to a safe value
a. Area cross section of object in the direction of motion
b. Density of the air
c. Viscosity of the air
d. None.
Explanation / Answer
1)(b) Gets larger the faster the diver moves
As the sky diver falls the magnitude of drag force keep on increasing until it reaches the weight of the skydiver.
2)(c)The drag force must equal the weight.
Terminal velocity is achieved when two forces that is the weight and air drag are equal.
3)(b) Fdrag=A*v^2
We know that,
Fdrag = 1/2 C rho V^2 A
4)(a) Area cross section of object in the direction of motion
After the chute opens the cross sectional acrea increases.
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