A 20.0-g Object is Placed Ag Morehead State University-p icioud as Eagle Mail Bl

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A 20.0-g Object is Placed Ag Morehead State University-p icioud as Eagle Mail Blackboard My Morehea HBO Go y Twitter If Facebook Jump to... Gra D 10/8/2017 1 1:55 PM 0 77.8/100 o 10/7/2017 03:15 PM Print Calculator Periodic Table Question 6 of 9 ncorrect Incorrect Map University Physics presented by Sapling Learning 1.25 m spring (with spring constant k equal to 25.0 N/m) that is compressed 10.0 cm. Once released, the object slides 1.25 m across the tabletop and eventually lands 0.96 m from the edge of the table on the floor, as shown in the figure Calculate the coefficient of friction between the table and the object. The sliding distance includes the compression of the spring and the tabletop is 1.00 m above the floor le 1.00 m Number 0.96 m 008 There is a hint availablel View the hint bottom dvider bar. Click on the on the divider bar again to hide the hint Close inde 8 0

Explanation / Answer

Given,

m = 20 g ; K = 25 N/m ; d = 1.25 m ; x = 10 m ; D =0.96 m ; h = 1 m

Let u be the required coefficient of friction

from eqn of motion

S = ut + 1/2 at^2

t = sqrt (2S/a)

this is when, u = 0 ; s = h = 1 m ; a = g = 9.81 m/s^2

t = sqrt (2 x 1/9.81) = 0.452 s

We know that

v = D/t = 0.96/0.452 = 2.13 m/s

from conservation of energy

KE = PE(spring) - Wf

where Wf is the work done against frictional forces

1/2 m v^2 = 1/2 k x^2 - u mg d

u = (k x^2 - mv^2)/2 m g d

u = (25 x 0.1^2 - 0.02 x 2.13^2)/ 2 x 0.02 x 9.81 x 1.25 = 0.325

Hence, u = 0.325

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