Normal No SpacingHeading Heading 2 10 ms-1 to a final velocity of l-Suppose a ca
ID: 1773383 • Letter: N
Question
Normal No SpacingHeading Heading 2 10 ms-1 to a final velocity of l-Suppose a car accelerates from an initial velocity ofXi Xt= +20 ms-1 in a time interval of 2 s. The average acceleration of the car is 2- Cyclist travels 200 miles in 10 hours. His speed is 3-A ball is thrown straight upward and reaches its highest point (5 meters above its starting point) after one second and then starts to fall back down. What is its instantaneous velocity at the instant it reaches its highest point? 4- A ball is thrown straight up with an initial velocity of 3 m/s. The ball is fairly heavy, so air resistance can be neglected. What will be its speed when it falls back to the level at which it was thrown 5- Convert 3.5 hours to minutes and 10 km to meters. 6- If air resistance is neglected, how long will it take for an object falling from rest to reach a speed of 200m/s? 7- A runner runs 500 m, east, then changes direction and runs 200 m, west. If the entire trip takes 50 s, what is the average speed and what is the average velocity? 8- A car is moving along the positive x-axis with a constant velocity of 60 m/s. Assuming that the car crosses the origin at t-0, at t = 1 s, the coordinate of the car will be 9. You start driving your car at 5:00pm. At 6:00pm you have driven 60 miles and stop to rest. At 6:05pm you get back onto the highway and drive an additional 60 miles to your destination where you arrive at 7:00pm. What the instantaneous rate of change of the distance at 6:03pm?Explanation / Answer
1) average accelaration is a = change in velocity / time taken
a = (final velocity - initial velocity ) / time taken
a = (V-Vo)/t
a = (20-10)/2 = 10/2 = 5 m/s^2
2) speed is v = distance travelled / time taken = 200 /10 = 20 mph
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