on in shell addition of forces Mesurement Two masses are connected by a light st
ID: 1773140 • Letter: O
Question
Explanation / Answer
a] decrease in potential energy = increase in KE
m1gh/2 - m2gh/2 = 0.5*(m1+m2) v^2
5.30*9.8*2 - 2.55*9.8*2 = 0.5*(5.30+2.55)*v^2
53.9 = 0.5*7.85 v^2
v = sqrt(53.9*2/7.85) = 3.706 m/s
b] The acceleration is same, distance h is double of previous case, so by third equation of motion, v = sqrt(2as)
v becomes sqrt 2 times,
v = 3.706*sqrt 2 = 5.241 m/s
c] Now string becomes loose and acceleration becomes g, by third equation of motion,
s = v^2/2g = 5.241^2/[2*9.8]
= 1.40 m
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