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w History Bookmarks Window Help HomewD w.flipitphysics.com/Course/ViewProblem?unititemiD-3094137&enrollmentID-259036; Yahoo Homework: HW7 Of CH21 Deadline: 100% until Monday, October 9 at 11:59 PM Electric Field from Point Charges 1 21314 5 6 Two polnt charges (q1 .-4uc and q2-8uc) are ted along the x- axis, separated by a distance d 9.9 cm. Point P ts located at (x.y) i d 1) what is E,(P), the value of the x-component of the electric field produced by q, and Q2 at point P? N/C Submit You currently have O subm/ssions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 2) What b E,iP), the value of the y component of the electric feld produced by q1 and q2 at point P N/C Submt You currently have 0 submissions for this question. Only 10 subm/ssion are allowed. You can make t0 more submissions for this question. 3)

Explanation / Answer

1)

r1 = distance of charge q1 from P = sqrt(d2 + d2) = sqrt(2) d = sqrt(2) (0.099) = 0.14 m

r2 = distance of charge q1 from P = d = 0.099

E1 = electric field by charge q1 at P = k q1/r12 = (9 x 109) (4 x 10-6)/(0.14)2 = 1.84 x 106 N/C

E2 = electric field by charge q2 at P = k q2/r22 = (9 x 109) (8 x 10-6)/(0.099)2 = 7.35 x 106 N/C

Exp = - E1 Sin45 = - (1.84 x 106) (Sin45) = - 1.3 x 106 N/C

2)

Eyp = - E1 Cos45 + E2 = - (1.84 x 106) (Cos45) + 7.35 x 106 = 6.1 x 106 N/C

3)

E3 = electric field by charge q3 at P = k q2/r22 = (9 x 109) (2.6 x 10-6)/(0.099)2 = 2.4 x 106 N/C

Exp = E3 - E1 Sin45 = (2.4 x 106 ) - (1.3 x 106) = 1.1 x 106 N/C

4)

electric field directly depends on magnitude of charge. hence the magnitude doubles but direction remain same

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