Four very long, current-carrying wires in the same plane intersect to form a squ

Question

Four very long, current-carrying wires in the same plane intersect to form a square with side lengths of 46.0 cm , as shown in the figure (Figure 1) . The currents running through the wires are 8.0 A, 20.0 A, 10.0 A, and I.

Part A

Find the magnitude of the current I that will make the magnetic field at the center of the square equal to zero.

Express your answer in amperes.

Hints

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Part B

What is the direction of the current I?

Hints

Four very long, current-carrying wires in the same plane intersect to form a square with side lengths of 46.0 cm , as shown in the figure (Figure 1) . The currents running through the wires are 8.0 A, 20.0 A, 10.0 A, and I.

Part A

Find the magnitude of the current I that will make the magnetic field at the center of the square equal to zero.

Express your answer in amperes.

Hints

I =   A  

SubmitMy AnswersGive Up

Part B

What is the direction of the current I?

Hints

What is the direction of the current ? upward downward

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10.0 A 8.0 A 20.0 A

Explanation / Answer

PartA) The wires are equidistant from center, so

B = uo/2pi r *(10+8-20 - i) = 0

10+8-20 - i =0

i = - 2 A

Hence magnitude of current is 2A answer

PartB) Because of negative science,

direction is downward.

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