FULL SCREEN PRINTER VERSION ·BACK In the circuit of the figure 8-4.00 kV, c-8.30

Question

FULL SCREEN PRINTER VERSION ·BACK In the circuit of the figure 8-4.00 kV, c-8.30R.-R2-R3-1.02 M. With C completely uncharged, switch S is suddenly closed (at t 0). At t = 0, what are (a) current/i in resistor 1 (b) current/2 in resistor 2, and (c) current 3 in resistor 3? At t oo (that is, after many time constants), what are (dh, (e), and (f);? what is the potential difference y across resistor 2 at (g)t-0 and (h)t “? Ri Re (a) Number (b) Number (c) Number (d) Number (e) Number (1) Number (9) Number (h) Number Units units Units Units Units Units Units Units the tolerance is +/-2

Explanation / Answer

Given,

V = 4000 V ; R1 = R2 = R3 = 1.02 M Ohm

The requivalnet resistance in the circuit needs to be determined.

R2 and R3 are in parallel so

R23 = R2 x R3/(R2 + R3)

R23 = 1.02 x 1.02/(1.02 + 1.02) = 0.51 m Ohm

Req = R23 + R1 = 1.02 + 0.51 = 1.53 M Ohm

The current in the circuit is:

I = V/Req = 4000/1.53 x 10^6 = 0.00261 A = 2.61 mA

a)I1 = = 0.00261 A

b)the drop across I1 is:

V1 = I1 R1 = 0.00261 x 1.05 x 10^6 = 2745 V

So the drop across parallel combination is:

V = 4000 - 2745 = 1255 V

I2 = V2/R2 = 1255/1.05 x 10^6 = 0.0012 A

Hence, I2 = 0.0012 A

c)I3 = V3/R3 = 1255/1.05 x 10^6 = 0.0012 A

Hence, I3 = 0.0012 A

after infinity the capacitor will get fully charge and there will be no current in the circuit so

d)I1 = 0

e)I2 = 0

f)I3 = 0

g)V2 = 1255 Volts

h)V2 = 0 at t = infinity

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