Home I Help H08 Begin Date: 9/19/2017 12:00:00 AM- -Due Date: 10/9/2017 11:00:00

Question

Home I Help H08 Begin Date: 9/19/2017 12:00:00 AM- -Due Date: 10/9/2017 11:00:00 PM End Date: 10/16/2017 11:00:00 PM (8%) Problem 2: A stationary soccer ball of mass m contact with the ball for 0.15 s. 0,92 kg is kicked with a constant force of F= 23 N. The player's foot is in t Status re for Potential Status Completed Submissions Attempts rema 4 5 6 per attem Feedback:0%deduction per feedback. 33% Part (b) what is the velocity of the ball right after contact with the foot of the player? 33% Part (e) If the ball left the player's foot at an angle -45° relative to the horizontal, how high h did it go in meters?

Explanation / Answer

a)

using impulse -change in momentum equation

m vi = F t

vi = (F t)/m

b)

vi = (F t)/m = 23 x 0.15/0.92 = 3.75 m/s

c)

consider the motion in Y-direction

Viy = initial velocity in Y-direction = vi Sin45 = 3.75 Sin45 = 2.65 m/s

Vfy = final velocity at the highest point = 0 m/s

a = acceleration = - 9.8

h = height gained

using the equation

Vfy2 = Viy2 + 2 a h

02 = (2.65)2 + 2 (-9.8) h

h = 0.36 m

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