A bar of length L and uniform density is held horizontally against a wall by a p

Question

A bar of length L and uniform density is held horizontally against a wall by a pivot at one end and a rope of tension T which pulls up and to the left making an angle with the vertical wall. The rope is attached to the bar at a distance l = cL from the wall. A mass M is resting at the end of the bar If the bar has total mass 2.2kg, the mass M-1.6kg, c-0.4, and the rope makes an angle of 38.4° with the wall, what is the magnitude of the force exerted by the rope (in other words, what is the tension T? Answer irn Newtons (N).

Explanation / Answer

Balancing torque about hinge at left,

T sin theta *l - MgL - mgL/2 = 0

T = ( (MgL+mgL/2)/[sin theta *0.4L]

= (1.6*9.8+2.2*9.8*0.5)/[sin 38.4 degree* 0.4]

= 106.5 N answer

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